4x^-4/5(y^2/3)/40/3y^-1/3(x^1/5)

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Solution for 4x^-4/5(y^2/3)/40/3y^-1/3(x^1/5) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((x^1)/5)*(((((((4*x^-4)/5)*((y^2)/3))/40)/3)*y^-1)/3) = 0

(x/5)*(((((((4*x^-4)/5)*((y^2)/3))/40)/3)*y^-1)/3) = 0

1/6750*x^-3*y = 0 // : 1/6750*y

x^-3 = 0

x należy do O

x belongs to the empty set

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